SmallScale Representation of New Earth
If Ezekiel's city is a small scale representation of the New
Jerusalem, what would the entire map of Ezekiel be, but a small scale
representation of the entire earth? After all, the inheritance God
promised Abraham was not just the land of Palestine:
For the promise, that he should be the heir of the world, was not to Abraham, or to his seed, through the law, but through the righteousness of faith.
(Romans 4:13)
But the meek shall inherit the earth; and shall delight themselves in the abundance of peace.
(Psalms 37:11)
Blessed are the meek: for they shall inherit the earth.
(Matthew 5:5)
The Basic Idea
Assuming that all thirteen strips of land are the same width, or
rather, assuming that Ezekiel's smallscale representation was intended
to represent thirteen strips of land of the same width, we have
a map that from top to bottom is:
13 x 25,000 cubits = 325,000 cubits.
Now we are ready for our calculations.
Perhaps the simplest way to put it is this:
If we enlarge Ezekiel's map till Ezekiel's city is the size of
Revelation's New Jerusalem, then Ezekiel's map encircles the globe.
The proportion of Ezekiel's city to
Revelation's New Jerusalem is the same as that of Ezekiel's map to the
earth's circumference:
Ezekiel's Map / Ezekiel's City * Revelation's City
= Earth's Circumference
Calculations a Bit Off
Let's first use the furlong
that most references tend to use, the English furlong of 660 feet. Since
the New Jerusalem is 3,000 furlongs to a side,
660 ft. x 3,000 furlongs / (5,280 feet / mi.) = 375
mi. (603.49 km)
Now we plug in the 4,500cubit length of Ezekiel's city and the
theoretical 325,000cubit length of Ezekiel's map:
325,000 cu. / 4,500 cu. * 375 mi. = 27,083 mi.
(43,585 km)
This amounts to an error of just under +9%, which is
close enough to be intriguing.
Calculations Right On
Since the apostle John didn't live in England, he never
heard of the English furlong. Instead, he used the Roman furlong. The
author has found three different measurements for the Roman furlong: 606.25 feet, 606.5 feet, and 606.84 feet.
Using a furlong of 606.25 feet:
606.25 ft. x 3,000 furlongs / (5,280 feet / mi.) =
344.46 mi. (554.34 km)
325,000 / 4,500 * 344.46 mi. = 24,878 mi. (40,036
km)
This result is .071% more than the polar circumference
and .098% less than the equatorial circumference.
Using a furlong of 606.5 feet:
606.5 ft. x 3,000 furlongs / (5,280 feet / mi.) =
344.6 mi. (554.56 km)
325,000 / 4,500 * 344.6 mi. = 24,888 mi. (40,052
km)
This result is .112% more than the polar circumference
and .057% less than the equatorial circumference.
Using a furlong of 606.84 feet:
606.84 ft. x 3,000 furlongs / (5,280 feet / mi.) =
344.80 mi. (554.89)
325,000 / 4,500 * 344.80 mi. = 24,902 mi. (40,075
km)
This result is .170% more than the polar circumference and .0001%
more than the equatorial circumference.
These extremely small margins of error make the subject more than
just intriguing.
The Size of the Temple
We can use the same ratios to calculate the size of the Holy Place
and Most Holy Place. Ezekiel's Holy Place was 20 by 40 cubits, and his
Most Holy Place was 20 by 20 cubits (Ezek. 41:2, 4).
Since exact precision isn't all that important, we'll just use the
furlong of 606.5 ft. We must make two calculations, one for 20 cubits
and the other for 40 cubits:
20 / 4,500 * 344.6 mi. = 1.53 mi.
40 / 4,500 * 344.6 mi. = 3.06 mi.
It is quite possible, therefore, that the heavenly
temple which will be outside the New Jerusalem will have a Holy Place
about 3 by 1.5 miles, and a Most Holy Place about 1.5 miles square. No
wonder the structure can accommodate millions of worshippers.
